Let height of a right circular cone =hcm and OA=rcm
Given, slant height of a right circular cone =3cm In △OAB, ∠BOA‌‌=90∘ (OB)2+(OA)2‌‌=(AB)2 [apply pythogoras theorem] (h)2+(r)2‌‌=(3)2 r‌‌=√9−h2 . . . (i) We know that, Volume of cone =‌
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πr2h V=‌
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(9−h2)×h [‌ from Eq. (i), ‌r=√9−h2] V=‌