If y=(\sin x)^{x}+\sin ^{-1} \sqrt{x}, then \frac{d y}{d x}

Correct Answer is : (sinx)x[xcotx+logsinx]+1√1−x×12√x

(\sin x)^{x}[\cot x+\log \sin x]+\frac{1}\sqrt{1-x} \times \frac{1}{2 \sqrt{x}

(\sin x)[x \cot x+\log \sin x]+\frac{1}\sqrt{1-x} \times \frac{1}{2 \sqrt{x}