According to Henry's Law, the solubility of a gas in a liquid at a particular temperature is directly proportional to the pressure of the gas above the liquid. The law can be mathematically expressed as:
S=kH⋅PWhere:
S is the solubility of the gas (in
moldm−3 ).
kH is Henry's law constant (in
moldm−3bar−1 ).
P is the partial pressure of the gas (in bar).
To find Henry's law constant for the given conditions, we need to rearrange the equation to solve for
kH :
kH=Given that the solubility
S=0.028moldm−3 and the partial pressure
P=0.346 bar, we can plug these values into the equation:
kH=To calculate
kHkH=moldm−3bar−1kH≈0.08092moldm−3bar−1 If you review the options provided, the closest value to 0.08092 is option A,
0.081moldm−3bar−1. Therefore, the correct option is: