NCHMCT JEE 2012 Question Paper with solutions for online practice

Let the height of the cylindrical tank = x cm
∴ Radius of tank =

3

4

x cm
We know that
1 ml = 1 cm3
38808 ml = 38808 cm3
∴ Volume of the cylindrical tank = πr2h
⇒ 38808 =

22

7

×(

3

4

x)2 × x
⇒ 38808 =

22

7

×

9

16

×x3
⇒ x3 =

38808×7×16

22×9

= 21952
∴ x = 28 xm
∴ Radius =

3

4

× 28 = 28 = 21 cm
∴ Diameter = 2 × 21 = 42 cm.