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NEET 2023 Physics and Chemistry Solved Paper Code C4 (Manipur)
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© examsnet.com
Question : 14
Total: 100
A particle moves with a velocity
(
5
^
i
−
3
^
j
+
6
^
k
)
m
s
−
1
horizontally under the action of constant force
(
10
^
i
+
10
^
j
+
20
^
k
)
N
. The instantaneous power supplied to the particle is :
[NEET 2023 mpr]
200
W
Zero
100
W
140
W
Validate
Solution:
👈: Video Solution
P
=
→
F
⋅
→
V
P
=
(
10
^
i
+
10
^
j
+
20
^
k
)
⋅
(
5
^
i
−
3
^
j
+
6
^
k
)
P
=
50
−
30
+
120
P
=
140
W
© examsnet.com
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