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NEET 2023 Physics and Chemistry Solved Paper Code C4 (Manipur)
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Question : 21
Total: 100
A ball is projected from point A with velocity
20
m
s
−
1
at an angle
60
∘
to the horizontal direction. At the highest point
B
of the path (as shown in figure), the velocity
v
m
s
−
1
of the ball will be:
[NEET 2023 mpr]
20
10
√
3
Zero
10
Validate
Solution:
👈: Video Solution
At the top most point of its trajectory particle will have only horizontal component of velocity
V
at top
=
v
cos
θ
=
20
×
1
2
=
10
m
∕
s
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