For the reaction, 2A+B2⇌2AB, Rate ∝[A]x[B2]y. On substituting the given data, we get From experiment 1 1.6×10−4∝[0.50]x[0.50]y ...(i) From experiment 2 , 3.2×10−4∝[0.50]x[1.00]y...(ii) From experiment 3 , 3.2×10−4∝[1.00]x[1.00]y ...(iii) On dividing equation (iii) by (ii), we get, 1=[
1.00
0.50
]x⇒1=2x⇒20=2x⇒x=0 Now, divide equation (ii) by equation (i) we get, 2=[
1.00
0.50
]y⇒2=2y⇒y=1 Thus rate equation is : Rate =k[A]0[B2]1=k[B2]