No. of oxidation states 3  4  5  6 Given order is correct Magnetic moment (μ)=√n(n+2) B.M For Ti3+‌‌n=1,‌‌‌μ=√1(1+2)=√3 B.M. For V3+‌‌‌n=2,‌‌‌μ=√2(2+2)=√8 B.M For Cr3+‌‌n=3,‌‌‌μ=√3(3+2)=√15 B.M For Mn3+‌n=4,‌‌μ=√4(4+2)=√24 B.M Thus magnetic moment : Ti3+<V3+<Cr3+<Mn3+ Melting point order : Mn  <  Ti  < Cr  < V          1245°C  1668°C 875°C  1900°C 2nd ionisation enthalpy order     Ti < V <  Mn < Cr kJ/mol  1320 1376 1513  1635
