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Class 12 NEET Chemistry Solutions Questions
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© examsnet.com
Question : 64
Total: 76
The relationship between osmotic pressure at
273
K
when
10
g
glucose
(
p
1
)
,
10
g
urea
(
p
2
)
,
and
10
g
sucrose
(
p
3
)
are dissolved in
250
m
L
of water is
(1996)
p
2
>
p
1
>
p
3
p
2
>
p
3
>
p
1
p
1
>
p
2
>
p
3
p
3
>
p
1
>
p
2
Validate
Solution:
Weight of glucose
=
10
g
Weight of urea
=
10
g
and weight of sucrose
=
10
g
.
The number of moles of glucose
(
n
1
)
=
Weight
Molecular weight
=
10
180
=
0.05
Similarly, number of moles of urea
(
n
2
)
=
10
60
=
0.16
and the number of moles of sucrose
(
n
3
)
=
10
342
=
0.03
The osmotic pressure is a colligative property and it depends upon the number of moles of solute.
since
n
2
>
n
1
>
n
3
,
therefore
p
2
>
p
1
>
p
3
© examsnet.com
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