1H2+1H2→2He2+ΔE The binding energy per nucleon of a deuteron =1.1 MeV ∴ Total binding energy =2×1.1=2.2 MeV The binding energy per nucleon of a helium nuclei =7MeV ∴ Total binding energy =4×7=28MeV Hence, energy released ΔE=(28−2×2.2)=23.6MeV
