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Test Index
Class 12 NEET Physics Dual Nature of Matter and Radiation
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© examsnet.com
Question : 50
Total: 104
The electron in the hydrogen atom jumps from excited state
(
n
=
3
)
to its ground state
(
n
=
1
)
and the photons thus emitted irradiate a photosensitive material. If the work function of the material is
5.1
e
V
, the stopping potential is estimated to be (the energy of the electron in nth state
E
n
=
−
13.6
n
2
e
V
)
(2010 Mains)
5.1 V
12.1 V
17.2 V
7 V
Validate
Solution:
Energy released when electron in the atom jumps from excited state
(
n
=
3
)
to ground state
(
n
=
1
)
is
E
=
h
υ
=
E
3
−
E
1
=
−
13.6
3
2
−
(
−
13.6
1
2
)
=
−
13.6
9
+
13.6
=
12.1
e
V
Therefore, stopping potential
e
V
s
=
h
υ
−
ϕ
0
=
12.1
−
5.1
[∵ Work function
ϕ
0
=
5.1
]
V
s
=
7
V
© examsnet.com
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