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Class 12 NEET Physics Electromagnetic Induction and Alternating Currents
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© examsnet.com
Question : 1
Total: 114
Let us consider two solenoids
A
and
B
, made from same magnetic material of relative permeability
µ
r
and equal area of cross-section. Length of
A
is twice that of
B
and the number of turns per unit length in
A
is half that of
B
. The ratio of self inductances of the two solenoids,
L
A
:
L
B
is
[NEET 2024 Re]
1
:
2
2
:
1
8
:
1
1
:
8
Validate
Solution:
L
=
µ
0
µ
r
×
n
×
A
×
N
L
=
µ
0
µ
r
n
×
A
×
N
I
×
I
L
=
µ
0
µ
r
×
n
2
×
A
×
I
⇒
L
∝
n
2
I
⇒
L
A
L
B
=
n
A
2
n
B
2
×
I
A
I
B
⇒
L
A
L
B
=
1
4
×
2
=
1
2
© examsnet.com
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