Magnetic field B = 5×10–5 T Number of turns in coil N = 800 Area of coil A = 0.05 m2 Time taken to rotate Δt = 0.1 s Initial angle θ1=0° Final angle θ2=90° Change in magnetic flux Δϕ = NBAcos90° – BAcos0° = – NBA = – 800 × 5 × 10–5 × 0.05 = – 2 × 10–3 weber e=−