×10t2=5t2 or t2=1 or t=1sec. It means that the third drop leaves after one second of the first drop, or each drop leaves after every 0.5 sec. Distance covered by the second drop in 0.5sec =
1
2
gt2=
1
2
×10×(0.5)2=1.25m Therefore distance of the second drop above the ground =5−1.25=3.75m