Class 11 NEET Physics Properties of Matter Questions

Total heat gained by ice is equal to the total heat lost by steam. For ice to completely convert into water, heat required is $m _{1} L _{ f }=1 \times 80= 8 0 \text{ cal}$ For steam to completely convert into water, heat released is $m _{2} L _{ v }=1 \times 540=540 \text{ cal}$ Hence, first 80 calories will not be enough for the steam to condense completely. Now, to convert melted water to $100^{\circ} \text{ C}$ from $0^{\circ} \text{ C}$, heat required is $m _{1} s (100-0)=1 \times 1 \times$ $100=100 \text{ cal}$ So, total energy required to heat ice to water $100^{\circ} \text{ C}$ is $100+80=180 \text{ cal}$. Hence, even this amount of energy is not enough for the steam to condense completely. Hence, the final temperature of the mixture will be $100^{\circ} \text{ C}$. Note- finally the mixture will consist of both steam and water at $100^{\circ} \text{ C}$.