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Class 11 NEET Physics Thermodynamics and Kinetic Theory
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© examsnet.com
Question : 56
Total: 105
A mass of diatomic gas
(
γ
=
1.4
)
at a pressure of 2 atmospheres is compressed adiabatically so that its temperature rises from 27°C to 927°C. The pressure of the gas in the final state is
(2011 Mains)
8 atm
28 atm
68.7 atm
256 atm
Validate
Solution:
For an adiabatic process
T
γ
P
γ
−
1
=
constant
∴
(
T
i
T
f
)
γ
=
(
P
i
P
f
)
γ
−
1
⇒
P
f
=
P
i
(
T
f
T
i
)
γ
γ
−
1
...(i)
Here,
T
i
=
27
°
C
=
300
K
,
T
f
=
927
°
C
=
1200
K
P
i
=
2
atm
,
γ
=
1.4
Substituting these values in eqn (i), we get
P
f
=
(
2
)
(
1200
300
)
1.4
1.4
−
1
=
(
2
)
(
4
)
1.4
0.4
=
2
(
2
2
)
7
2
=
(
2
)
(
2
)
7
=
2
8
=
256
atm
© examsnet.com
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