NIACL Model Paper 6 with solutions for free online practice

(11-15):
@ ⇒ ≤ , % ⇒ ≥ , * ⇒ > , © ⇒< . $ ⇒=< br> B% K ⇒ B ≥ K
K $ T ⇒ K = T
T * F ⇒ T > F
H © F ⇒ H < F Therefore, B ⇒ K=T> F > H
F < B : True
Conclusions
I. B $ T  B = T : Not True
II. T © B ⇒ T < B : Not True
T is either smaller than or equal to B.
Therefore, either I or II is true.
III. H © K ⇒ H < K : True
IV. F © B ⇒ F < B : True