Let A has ₹ x and B has ₹ y A B ₹ x ₹y According to the question, x+400=
5
4
×(y−400) ⇒4x−5y=−3600...(i) and y+200=
7
2
(x−200) ⇒7x−2y=1800...(ii) From (i) and (ii) 4x–5y=–3600 ]×2 7x–2y=1800 ]×5 8x–10y=–7200 35x–10y=9000 −+− –––––––––––– 27x=16200 ⇒x=600 7×600–2y=1800 ⇒2y=4200–1800 =2400 ⇒y=1200 Hence, B has ₹ 1200.