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NIMCET 2014 Question Paper with solutions
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© examsnet.com
Question : 3
Total: 120
A chain of video stores sells three different brands of DVD players. Of its DVD player sales 50% are brand 1, 30% are brand 2 and 20% are brand 3 Each manufacturer offers one year warranty on parts and labour. It is known that 25% of brand 1 DVD playersrequire warranty repair work, whereas the corresponding percentage for brands 2 and 3 are 20% and 10% respectively. The probability that a randomly selected purchaser has a DVD player that will need repair while under warranty, is
0.795
0.205
0.1250
0.060
Validate
Solution:
Let probability of sale of brand 1 is P(A).
Similarly, for brand 2 is P(B)
and brand 3 is P(C)
Given,
P (A) =
50
100
=
1
2
P (B) =
30
100
=
3
10
P (C) =
20
100
=
1
5
and also tet the probability of required warranty work of brand (1) is P (A)
Similarly, for brand 2 is P(B)
and for brand 3 is P(C).
∴ P (A) =
25
100
=
1
4
P (B) =
20
100
=
1
5
P (C) =
10
100
=
1
10
Now, required probability =
1
2
×
14
+
3
10
×
1
5
+
1
5
×
1
10
=
1
8
+
3
50
+
1
50
=
50
+
24
+
8
400
=
82
400
= 0.205
© examsnet.com
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