P=(F87B)16=1111100001111011 2's complement=1111100001111011 +1 –––––––––––––––– 0000011110000101 –––––––––––––––– (00011110000101)2 ↓↓↓↓↓↓↓↓↓↓↓ 10245122561286432168421 Value in decimal is (1925)10, Hence, P=−1925 So, now doing 8′P=(−15400)10 Since, a negative number we have to find the 2's complement of −15400 Binary of 15400 = 0011 1100 00101000