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NTSE Stage 2 MAT 2017 Question Paper
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© examsnet.com
Question : 37
Total: 100
The square of the length of a rod AB is 72
cm
2
. If we place the rod in the corner of a room, so that the end A is always on the edge between the two walls of the corner and the end B is always on the floor, what is the maximum possible area of the triangle formed by the rod, the edge between the walls and the floor?
6
cm
2
12
cm
2
18
cm
2
24
cm
2
Validate
Solution:
From the given question
Area of right triangle is maximum, when base is equal to perpendicular.
a
2
+
a
2
=
(
√
72
)
2
a
=
6
cm
∴ Area
=
1
2
×
6
×
6
=
18
cm
2
So the maximum possible area of the triangle formed by rod is 18
cm
2
© examsnet.com
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