In beaker (y), of 100 gm of ice at 0°C is added then final temperature = 0°C But in beaker (x), if 100 gm. of water is added then final temperature =100×1(Tf−0) =100×(20−Tf)=10°c ∴ Water in the beaker (y) will be colder than water in beaker (x) because of absorption of latent heat.