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NTSE Stage 2 SAT 2017 Question Paper
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© examsnet.com
Question : 17
Total: 100
1.80 g of glucose is dissolved in 36.00 g of water in a beaker. The total number of oxygen atoms in the solution is
12.405
×
10
23
12.405
×
10
22
6.022
×
10
23
6.022
×
10
22
Validate
Solution:
As per unitary method
Number of oxygen atoms will be
6
180
×
1.8
=
0.06
NA
∴ In 36.0 gm of water, number of oxygen atoms are
NA
18
×
36
=
2
NA
⇒ total number of oxygen atoms
=
(
0.06
+
2
)
NA
=
2.06
NA
=
2.06
×
6.022
×
10
23
=
1.2405
×
10
24
=
12.405
×
10
24
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