NTSE Stage 2 SAT 2018 Exam Question Paper

Let the side of square be a.
Then, radius of inner circle = half of side square =

a

2

Therefore, the area of inner circle =π(radius)2
=π(‌‌

a

2

)2=π‌‌

a2

4

Since, the diagonal of the square=√2a
Then, radius of outer circle = half of diagonal of square =

√2a

2

Hence, the area of outer circle =π(‌‌

√2a

2

)2=π‌‌

2a2

4

Hence, the required ratio of the areas of inner circle to outer circle is ‌‌

a2

4

:‌‌

2a2

4

=1:2