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Pipes and Cisterns Practice Test 3 with solutions
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© examsnet.com
Question : 4
Total: 7
A tank can be filled separately by two taps A and B in 45 minutes and 36 minutes respectively. A tap C at the bottom can empty the full cistern in 30 minutes. If the tap C is opened 7 minutes after the two taps A and B are opened, find when the cistern will be full?
46 minutes
25 minutes
14 minutes
None of these
Validate
Solution:
In 7 minutes (A + B) together will fill = 7 ×
(
1
45
+
1
36
)
=
7
×
1
20
=
7
20
tank
Unfilled portion of tank after 7 minutes = 1 -
7
20
=
13
20
tank
Now, tank filled in 1 minute when A, B and C are opened =
1
45
+
1
36
−
1
30
=
1
60
∴ Time required to fill
13
30
tank =
60
×
13
20
= 39 minutes
Hence, total time required to fill the tank = 7 + 39 = 46 minutes.
© examsnet.com
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