Pipes and Cisterns Practice Test 3 with solutions

Time taken by Pipe ‘P’ = 3 hours
Time taken by Pipe ‘Q’ = 6 hours
Part of cistern filled by both P and Q in one hour
=

1

3

+

1

6

=

2+1

6

=

1

2

So, time taken by both Pipe ‘P’ and ‘Q’ = 2 hours
So, time taken by Pipe ‘C’ 2 hours
Part of cistern filled by all three in 1 hour =

1

3

+

1

6

+

1

2

=

2+1+3

6

=

6

6

= 1
So, if all the three pipes are opened simultaneously they will fill the cistern in 1 hour.