Area of the rectangular paper = 8 × 6 = 48 sq. cm. Since Diameter of the greatest possible circle will be 6 cm. ∴ Radius of the circle (R) = 6/2 = 3 cm Now, Area of the circle = πR2 = π × 3 × 3 = 9π sq. cm ∴ Area of the remaining paper = (48 – 9π) sq. cm.