ABCD is a quadrilateral. AB || DC AD || BC In equilateral ΔABE, perimeter = 6 units Side = 2 cm Area of the equilateral triangle =
√3
4
a2 =
√3×2×2
4
= √3units2 ... (1) units2 In the right angle triangle ΔADE, AE = 2 unit DE = 1 unit (AD)2+(DE)2 = (AE)2 (AD)2+(1)2 = (2)2 AD = √4−1 = √3 Area of Δ ADE =
1
2
×1×√3 =
√3
2
... (2) Similarly, area of Δ ECB =
1
2
×1×√3 =
√3
2
... (3) Adding(1), (2) and (3), Area of quadrilateral ABCD = √3+