Geometry Practice Test 4

AB || CD
BE || FH
CD is a straight line.
∠HEC + ∠HEB + ∠BED = 180°
∠HEB = 180° - (60° + 50°)
= 180° - 110°
∠HEB = 70°’
BE || FH
HE is a transversal line.
So, the sum of two interior angles on the same side with a transversal line is 180°.
∠FHE + ∠HEB = 180°
∠FHE = 180° - 70 °
∠FHE = 110°