Let two ships started from point O at the speed of 30 km/hr 0 and 20 km/hr respectively, after two hours they reach at points A and B. Now, ∠ NOA = 32° and ∠ SOB = 58°, Then, ∠ AOB = 180° – (32° + 58°) = 90° Since Δ AOB is a right triangle in which OA = 2 × 30 = 60 km and OB = 2 × 20 = 40 km Since, AB=√OA2+OB2=√602+402=20√13km