Let CD = h unit be the height of the tower and A and B be the two points on the ground, such that DA = a; DB = b; ∠DAC = α and ∠DBC = 90° – α From right triangle ADC, CD = h = a tan α ...(i) From right triangle BDC, CD = h = b tan (90° – α) = b cot α ...(ii) Multiplying equations (i) and (ii), we get h2=a‌tan‌α.b‌cot‌α Hence, h=√ab