Let AB = 24 ft and CD = 6 ft be the heights of the pillar and man respectively. Here, ∠ACE = α; ∠CBD = 90° – α; Now from right triangle CDB, BD = 6 cot (90° – α) = 6 tan α ∴tan‌α=
BD
6
...(i) From right triangle ACE, tan‌α=
18
EC
=
18
BD
...(ii) (∵ EC = BD) Now from (i) and (ii) we get,