Let AB = h m be the height of cliff and CD = x m be the height of the tower and also ∠ ADB = 60° and ∠ ACE = 30°. Now, from the figure, AE = (h – x)m From right triangle ABD, BD = h cot 60° =
h
√3
m From right triangle CEA, (h – x) = EC tan 30° = BD tan 30° ⇒h−x=