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LCM and HCF Practice Test 1
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© examsnet.com
Question : 9
Total: 40
Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then find the sum of the digits in N.
8
6
5
4
Validate
Solution:
👈: Video Solution
N = HCF of (4665 – 1305), (6805 – 4665) and (6905 – 1305)
N = HCF of 3360, 2240 and 5600.
Hence, N = HCF of 3360, 2240 and 5600 = 1120
Sum of digits in N = 1 + 1 + 2 + 0 = 4.
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