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LCM and HCF Practice Test 2
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© examsnet.com
Question : 6
Total: 40
Let N be the greatest natural number that will divide 13,511, 13,903 and 14,589 leaving the same remainder in each case. The sum of digits of N is:
10
13
15
17
Validate
Solution:
We can solve this by division method
x = 13,511 y = 1,390, z = 14,589
(
y
−
x
)
=
13
,
903
−
13
,
511
=
392
(
z
−
y
)
=
14
,
589
−
13
,
903
=
686
(
z
−
x
)
=
14
,
589
−
13
,
511
=
1
,
078
HCF of 392, 686, 1,078 is 98
Sum of digits of N is 17.
© examsnet.com
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