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LCM and HCF Practice Test 4
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© examsnet.com
Question : 11
Total: 40
The product of two numbers is 2028 and their HCF is 13. The number of such pair is
4
3
2
1
Validate
Solution:
Let the two numbers be 13x and 13y
Now,
13
x
×
13
y
=
2028
∴
x
y
=
2028
13
×
13
=
12
Then, co-primes with product 12 are (1, 12) and (3, 4)
Hence, the requried numbers are
(
13
×
1
,
13
×
12
)
and
(
13
×
3
,
13
×
4
)
.
So, there are two such pairs.
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