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LCM and HCF Practice Test 5
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© examsnet.com
Question : 19
Total: 33
The smallest number exactly divisible by 3, 4, 6 and 8 is
26
24
25
28
Validate
Solution:
L.C.M. of 3, 4, 6 and 8
∴ The required number = LCM of the given numbers = 2 × 2 × 3 × 2 = 24.
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