Examsnet
Unconfined exams practice
Home
Exams
Banking Entrance Exams
CUET Exam Papers
Defence Exams
Engineering Exams
Finance Entrance Exams
GATE Exam Practice
Insurance Exams
International Exams
JEE Exams
LAW Entrance Exams
MBA Entrance Exams
MCA Entrance Exams
Medical Entrance Exams
Other Entrance Exams
Police Exams
Public Service Commission (PSC)
RRB Entrance Exams
SSC Exams
State Govt Exams
Subjectwise Practice
Teacher Exams
SET Exams(State Eligibility Test)
UPSC Entrance Exams
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Careers
Contact Us
Our Apps
Privacy
Test Index
Mensuration Practice Test 4
Show Para
Hide Para
Share question:
© examsnet.com
Question : 14
Total: 40
The radius of the base of a right circular cone is doubled keeping its height fixed. The volume of the cone will be:
Three times of the previous volume
Four times of the previous volume
2 times of the previous volume
double of the previous volume
Validate
Solution:
Radius of the cone = 2 cm
Height = 6 cm.
Radius of the cone R = 4 cm
Height remain fixed = 6 cm.
Volume of the cone =
1
3
π
r
2
h
=
π
(
2
)
26
3
= 8π
Volume of the new cone =
1
3
π
R
2
h
=
1
3
π
(
4
)
2
6
= 32π
Volume of the new cones is four times of the previous volume.
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
Prev Question
Next Question
Examsnet