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Mensuration Practice Test 4
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© examsnet.com
Question : 40
Total: 40
A tent is of the shape of a right circular cylinder up to a height of 3 m and then becomes a right circular cone with the maximum height of 13.5 m above the ground. If the radius of the base is 14 m, the cost of painting the inner side of the tent at the rate of Rs 2 per sq. m is:
Rs 2,050
Rs 2,060
Rs 2,068
Rs 2,080
Validate
Solution:
Slant height of the cone =
√
(
14
)
2
+
(
10.5
)
2
=
√
196
+
110.25
=
√
306.25
= 17.5 m
Required area =
2
π
r
h
+
π
r
l
= πr (2h + l)
=
22
7
×
14
(
6
+
17.5
)
=
22
7
× 14 × 23.5 =
10.4
c
m
2
Total cost = 1,034 × 2 = Rs 2,068
© examsnet.com
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