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Number System Practice Test 6
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© examsnet.com
Question : 5
Total: 12
If the difference in the squares of two natural numbers is 29, find the sum of the squares of the numbers.
409
400
434
421
484
Validate
Solution:
Let the two numbers be x and y.
x
2
−
y
2
=
29
(
x
+
y
)
(
x
−
y
)
=
29
×
1
x + y = 29 and (x - y) = 1
So, x = 15 and y = 14
x
2
+
y
2
=
15
+
14
2
= 225 + 196 = 421.
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