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Problems based on Numbers Test 6
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© examsnet.com
Question : 4
Total: 40
If
1
3
+
2
3
+
…
+
9
3
=
2
,
025
, then the approximate value of
(
0.11
)
3
+
(
0.22
)
3
+
…
+
(
0.99
)
3
is:
0.2695
0.3695
2.695
3.695
Validate
Solution:
The given expression
1
3
+
2
3
+
…
+
9
3
=
2
,
025
The value of
(
0.11
)
3
+
(
0.22
)
3
+
…
+
(
0.99
)
3
=
(
0.11
)
3
(
1
3
+
2
3
+
.
.
.
+
9
3
)
=
(
0.11
)
3
(
2025
)
=
0.001331
×
2025
= 2.695275 = 2.695
© examsnet.com
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