Let ‘a’ be the first term and ‘d’ be the common difference. Then t4=16⇒a+3d=16 ……(i) t6=24⇒a+5d=24 ……(ii) Subtracting (i) from (ii) we get 2d = 8 ⇒ d = 4 Putting d = 4 in equation (i) we get a + 3 (4) = 16 ⇒ a = 4 Now t11=a+10d=4+10(4)=44⇒t11=44