A ∪ B = {1, 3, 5, 7, 11, 13, 15, 17} ∪ {2, 4, 6, 8, 9,10, 12, 14, 16, 18}
= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18}
A′ = {2, 4, 6, 8, 9, 10, 12, 14, 16, 18}
B′ = {1, 3, 5, 7, 11, 13, 15, 17}
(A ∪ B) ∩ B′ = {2, 4, 6, 8, 9, 10, 12, 14, 16, 18}
Now A′∩((A ∪ B) ∩ B′) = ϕ
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