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Surds and Indices Practice Test 2
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© examsnet.com
Question : 3
Total: 17
(
x
b
x
c
)
1
b
c
×
(
x
c
x
a
)
1
a
c
×
(
x
a
x
b
)
1
a
b
is equivalent to:
x
b
2
−
a
c
1
x
(
a
b
+
b
2
−
c
2
)
x
(
a
3
+
b
3
+
c
3
−
a
b
c
)
1
Validate
Solution:
(
x
b
x
c
)
1
b
c
=
(
x
b
−
c
)
1
b
c
=
x
(
1
c
−
1
b
)
Similarly,
(
x
c
x
a
)
1
a
c
=
x
(
1
a
−
1
c
)
and
(
x
a
x
b
)
1
a
b
=
x
(
1
b
−
1
a
)
∴
(
x
b
x
c
)
1
b
c
×
(
x
c
x
a
)
1
a
c
×
(
x
a
x
b
)
1
a
b
=
x
(
1
c
−
1
b
)
×
x
(
1
a
−
1
c
)
×
x
(
1
b
−
1
a
)
=
x
(
1
c
−
1
b
+
1
a
−
1
c
+
1
b
−
1
a
)
=
x
0
=
1
© examsnet.com
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