By statement I Perimeter of rhombus = 4a = 60 ⇒ a = 15 cm
By statement II One diagonal = 18 cm We know that diagonals of a rhombus cut each other at 90 degree. So, OP2=PS2−SO2 So,OP2=PS2−SO2 ⇒ OP2=152−92 ⇒OP2=152-92 ⇒OP2 = 225 - 81 = 144 ⇒ OP = 12 cm So length of other diagonal is = 2 × 12 = 24 cm By statement III Sum of diagonals = 42 other diagonal = 42 - 18 = 24 cm ∴ Area of Rhombus PQRS = 1/2 × d1 × d2 ⇒ 1/2 × 18 × 24 = 216 cmsq Hence only statement III is sufficient to answer or statement I & II together.