(4) No. of days Adil (A) and Biren (B)together takes = 20 days
No. of days Biren (B) and Chirag (C)takes = 50 days
No. of days Adil (A) and Chirag (C)takes = 40 days
The total work done = LCM of (20,50, 40) = 200
Work Done by A + B in a day
=
= 10unit
Work done by B and C in a day
=
= 40 unit
Work done by A and C in a day
=
= 5unit
Hence, A + B = 10 ...(i)
B + C = 4 ...(ii)
A + C = 5 ...(iii)
Solving simultaneously equation (i),(ii) & (iii), we get
A = 5.5 units in 1 day
B = 4.5 units in 1 day
Total time taken by A
=| Complete work |
| Work done in single day |
=Total Taken time by
B=Ratio of time taken by A to that taken by B
⇒:=4.5:5.5=9:11