(1) Given in a right angle Δ H = B + 1 B = 49 + P We know that in a right angled triangle, P2+B2=H2(From Pythagoras theorem) ⇒(B−49)2+B2=(B+1)2 ⇒B2+(49)2−98B+B2=B2+1+2B ⇒B2−100B+2400=0 B=
100±√10000−9600
2
⇒B=
100±√400
2
=60,40 B > 49; B ≠ 40 and B=60 P = B − 49 = 60 − 49=11 cm