(c) There are 5 + 7 = 12 balls in the bag and out of these two balls can be drawn in 12C2 ways. There are 5 green balls, therefore, one green ball can be drawn in 5C1 ways; similarly, one red ball can be drawn in 7C1 ways so that the number of ways inwhich we can draw one green ball and the other red is 5C1×7C1.Hence, P (one green and the other red)