Since the square of any real number is non-negative, every point on the graph of the quadratic equation y=(x−2)2 in the xy-plane has a non-negative y-coordinate. Thus, y≥0 for every point on the graph. Therefore, the equation y=(x−2)2 has a graph for which y is always greater than or equal to −1. Choices A, B, and D are incorrect because the graph of each of these equations in the xy-plane has a y-intercept at (0,−2). Therefore, each of these equations contains at least one point where y is less than −1.