Multiplying each side of x+y=0 by 2 gives 2x+2y=0.Then, adding the corresponding sides of 2x+2y=0 and 3x−2y=10 gives 5x=10.Dividing each side of 5x=10 by gives x=2 ,Finally,substituting 2 for x in x+y=0 gives 2+y=0, or y=−2 Therefore, the solution to the given system of equations is (2,−2). Alternatively the equation x+y=0 can be rewritten as x = −y, and substituting for −y in 3x−2y=10 gives 5x=10, or x=2. The value of y can then be found in the same way as before. Choices A, C, and D are incorrect because when the given values of x and y are substituted into x+y=0 and 3x−2y=10, either one or both of the equations are not true. These answers may result from sign errors or other computational errors